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[Haskell][23] Adding Solution

Vinicius Teshima 4 月之前
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共有 2 个文件被更改,包括 43 次插入1 次删除
  1. 43 0
      haskell/src/0023.hs
  2. 0 1
      haskell/src/Utils.hs

+ 43 - 0
haskell/src/0023.hs

@@ -0,0 +1,43 @@
+{-
+A perfect number is a number for which the sum of its proper divisors is exactly equal to the number. For example, the sum of the proper divisors of 28 would be 1 + 2 + 4 + 7 + 14 = 28, which means that 28 is a perfect number.
+A number n is called deficient if the sum of its proper divisors is less than n and it is called abundant if this sum exceeds n.
+
+As 12 is the smallest abundant number, 1 + 2 + 3 + 4 + 6 = 16, the smallest number that can be written as the sum of two abundant numbers is 24. By mathematical analysis, it can be shown that all integers greater than 28123 can be written as the sum of two abundant numbers. However, this upper limit cannot be reduced any further by analysis even though it is known that the greatest number that cannot be expressed as the sum of two abundant numbers is less than this limit.
+Find the sum of all the positive integers which cannot be written as the sum of two abundant numbers.
+-}
+
+import Utils
+
+import Data.List
+
+--import Data.Map (Map)
+--import qualified Data.Map as Map
+
+import Data.IntSet (IntSet)
+import qualified Data.IntSet as IntSet
+
+import Debug.Trace
+
+isAbundant :: Int -> Bool
+isAbundant x = (divs x |> sum) > x
+
+abundants :: [Int]
+abundants = iterate (+1) 1 |> take 28124 |> filter isAbundant
+abundantsSet :: IntSet
+abundantsSet = IntSet.fromList abundants
+
+f :: Int -> Bool
+f n = go' abundants
+  where
+    go' [] = False
+    go' [x] = IntSet.member (n-x) abundantsSet
+    go' (x:xs)
+      | x >= n                           = False
+      | IntSet.member (n-x) abundantsSet = True
+      | otherwise                        = go' xs
+
+solution :: Int
+solution = iterate (+1) 1 |> take 28123 |> filter (\x -> (f x) == False) |> sum
+
+main :: IO ()
+main = putStrLn ("Solution: " ++ show solution)

+ 0 - 1
haskell/src/Utils.hs

@@ -212,7 +212,6 @@ module Utils where
   divs :: Int -> [Int]
   divs 0 = []
   divs 1 = [1]
-  divs 2 = [1, 2]
   divs x = filter (\x' -> (mod x x') == 0) (take (x-1) (iterate (+1) 1))
 
   flattenTupleList :: [(a, a)] -> [a]