// 3452. Sum of Good Numbers

function sumOfGoodNumbers(nums: number[], k: number): number {
    let sum = 0;
    let i: number = 0;
    const limit: number = nums.length;
    while ( i < limit ) {
        let v: number = nums[i];
        let lg: boolean = true;
        if ( i-k >= 0 ) { lg = v > nums[i-k]; }
        let rg: boolean = true;
        if ( i+k < limit ) { rg = v > nums[i+k]; }

        if ( lg == true && rg == true ) { sum += v; }

        ++i;
    }
    return sum;
};

function main() {
    function r(nums: number[], k: number, exp: number) {
        console.log(`sumOfGoodNumbers([${nums}], ${k}) = ${sumOfGoodNumbers(nums, k)} | exp: ${exp}`)
    }

    r([1,3,2,1,5,4], 2, 12)
    r([2,1], 1, 2)
    r([45,38,20], 1, 45)
}

main()